The type must be a reference type in order to use it as parameter 'T' in the generic type or method 發表於 2018-10-10 更新於 2020-11-10 分類於 程式語言 The type must be a reference type in order to use it as parameter ‘T’ in the generic type or methodStackOverflow : The type must be a reference type in order to use it as parameter ‘T’ in the generic type or method